y-f(t)=f'(t)(x-t)∴Yq=f(t)-t'f(t)(自己带入t不想打别说你不会)Yq<1。a>(e^t-t*e^t-1)/(t^2)所以a要大于(e^t-t*e^t-1)/(t^2)最大值。令h(t)=(e^t-t*e^t-1)/(t^2)求导:h'(t)=[e^t(t^2-2t 2)-2]/(t^2)自己求导化简。再令m(t)=e^t(t^2-2t 2)-2再求导可得m'(t)=e^t*t^2恒大于0所以m(t)为增函数所以当0<t<1时h(t)最大值为h(1)=-1所以a>-1