#include<stdio.h>
int main(void)
{
int num;
num=1;
printf("i am a simple");
printf(" computer.\n");
printf("my favorite number is %dbecause it is the first.\n",num);
return 0;
}

#include<stdio.h>
int main (void)
{
char name[40];
scanf("%s",&name);
printf("我打的字是%s",name);
return 0;
}

#include<stdio.h>
int main (void)
{
float weight;
float value;
printf("are you worth your weight in platinum?\n");
printf("let's check it out.\n");
printf("please enter your weight in pounds:");
scanf("%f",&weight);
value=1700.0*weight*14.5833;
printf("your weight in platinum is worth $%.2f.\n",value);
printf("you are easily worth that!if platinum prices drop,\n");
printf("eat more to maintain your value.\n");
return 0;
}

#include <stdio.h>
int main (void)
{
int ten;
printf("请你输入将要转换为八进制,十六进制的十进制数:");
scanf("%d",&ten);
printf("%#o是你要的八进制表示，%#X是你要的十六进制表示",ten,ten);
return 0;
}

#include <stdio.h>
int main (void)
{
float a=24.0000;
printf("%f的\nfloat值是%f\nlongfloat值是%lf\n指数式值是%e\n",a,a,a,a);
return 0;
}

#include<stdio.h>
int main(void)
{
char name[40];
printf("你的名字？\n");
scanf("%s", name);
printf("你好%s,我是一个机器人\n",name);
getchar();
printf("很高兴认识你。\n");
getchar();
printf("我们可以做朋友吗？%s\n",name);
getchar();printf("不论如何很高兴你能打开这个程序\n");
getchar();
printf("再见");
return 0;
}

#include<stdio.h>
int main (void)
{
char grade='A';
printf("这个A的ASCII代码是%d",grade);
return 0;
}

#include<stdio.h>
int main(void)
{
char name[40];
int a;
printf("欢迎使用本程序。\n");
printf("我是(●—●)，你叫什么名字?\n");
scanf("%s",&name);
printf("\n你好%s，见到你很高兴。\n",name);
getchar();
printf("\n你知道吗？\n\n当你告诉我一个十进制的数时，我可以告诉你它的十六进制表达\n");
getchar();
printf("让我们试试吧，请告诉我这个数字是:______\b\b\b\b\b\b");
scanf("%d",&a);
printf("\n%d的十六进制数是%#X\n",a,a);
getchar();
printf("\n和你聊天真的很愉快\n");
getchar();
printf("但是我要走了。\n");
getchar();
printf("期待下次和你见面\n");
printf("\n
再 见\n");
return 0;
}

#include<stdio.h>
#include<math.h>
int main()
{
double a,b,c,disc,x1,x2,p,q;
printf("若有一元二次方程一般形式形如:\n a*x^2+b*x+c=0\n且分别输入a,b,c\n");
printf("a=");
scanf("%lf",&a);
printf("\nb=");
scanf("%lf",&b);
printf("\nc=");
scanf("%lf",&c);//6到12条是我加的
disc=b*b-4*a*c;
p=-b/(2.0*a);
q=sqrt(disc)/(2.0*a);
x1=p+q;x2=p-q;
printf("有解得:\nx1=%7.2f\nx2=%7.2f\n",x1,x2);
return 0;
}