已解决,谢谢各位

楼下发代码,需要的拿,工作中求二日期之间工作日天数还是很常见的

字数太多了,分段发吧

package com.gwideal.util;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Date;
import java.util.Iterator;
import java.util.List;
public final class GetWorkDay {
/**
* @param args
*/
public static void main(String[] args) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
List<Date> holidays = new ArrayList<Date>();
try {
holidays.add(sdf.parse("2013-10-01"));
holidays.add(sdf.parse("2013-10-02"));
holidays.add(sdf.parse("2013-10-03"));
holidays.add(sdf.parse("2013-10-04"));
holidays.add(sdf.parse("2013-10-05"));
holidays.add(sdf.parse("2013-10-06"));
holidays.add(sdf.parse("2013-10-07"));
} catch (ParseException e) {
e.printStackTrace();
}
// TODO Auto-generated method stub
GetWorkDay o = new GetWorkDay();
Long b = o.getWorkdayTimeInMillisExcWeekendHolidays(
"2013-10-09 15-00-00", "2013-10-24 9-30-00",
"yyyy-MM-dd HH-mm-ss", holidays);
System.out.println(b);
System.out.println(o.formatDuring(b));
}
/**
* 获取两个时间之内的工作日时间（只去掉两个日期之间的周末时间，法定节假日未去掉）
*
* @param start
* -起始时间，共有3个重载方法，可以传入long型，Long型，与Date型
* @param end
* -结束时间，共有3个重载方法，可以传入long型，Long型，与Date型
* @return Long型时间差对象
*/
private Long getWorkdayTimeInMillis(long start, long end,
List<Date> listHolidays) {
// 如果起始时间大于结束时间，将二者交换
if (start > end) {
long temp = start;
start = end;
end = temp;
}
// 根据参数获取起始时间与结束时间的日历类型对象
Calendar sdate = Calendar.getInstance();
Calendar edate = Calendar.getInstance();
sdate.setTimeInMillis(start);
edate.setTimeInMillis(end);
// 计算指定时间段内法定节假日天数的毫秒数
long holidays = 0;
if (listHolidays != null) {
holidays = getHolidaysInMillis(start, end, listHolidays);
listHolidays.clear();
}
// 如果两个时间在同一周并且都不是周末日期，则直接返回时间差，增加执行效率
if ((sdate.get(Calendar.YEAR) == edate.get(Calendar.YEAR))
&& (sdate.get(Calendar.WEEK_OF_YEAR) == edate
.get(Calendar.WEEK_OF_YEAR))
&& (sdate.get(Calendar.DAY_OF_WEEK) != 1 && sdate
.get(Calendar.DAY_OF_WEEK) != 7)
&& (edate.get(Calendar.DAY_OF_WEEK) != 1 && edate
.get(Calendar.DAY_OF_WEEK) != 7)) {
return new Long(end - start - holidays);
}
// 如果两个时间在同一周并且都是周末日期，则直接返回0
if ((sdate.get(Calendar.YEAR) == edate.get(Calendar.YEAR))
&& (sdate.get(Calendar.WEEK_OF_YEAR) == edate
.get(Calendar.WEEK_OF_YEAR)-1)
&& (sdate.get(Calendar.DAY_OF_WEEK) == 1
|| sdate.get(Calendar.DAY_OF_WEEK) == 7)
&&
(edate.get(Calendar.DAY_OF_WEEK) == 1
|| edate.get(Calendar.DAY_OF_WEEK) == 7)) {
start=validateStartTime(sdate);
end=validateEndTime(edate);
long result=end - start - holidays;
return new Long(result>0?result:0);
}
start=validateStartTime(sdate);
end=validateEndTime(edate);
// 首先取得起始日期与结束日期的下个周一的日期
Calendar snextM = getNextMonday(sdate);
Calendar enextM = getNextMonday(edate);
// 获取这两个周一之间的实际天数
int days = getDaysBetween(snextM, enextM);
// 获取这两个周一之间的工作日数(两个周一之间的天数肯定能被7整除，并且工作日数量占其中的5/7)
int workdays = days / 7 * 5;
// 计算最终结果，具体为：workdays加上开始时间的时间偏移量，减去结束时间的时间偏移量
long result = (workdays * 24 * 3600000
+ calcWorkdayTimeInMillis(sdate, edate, start, end) - holidays);
return result > 0 ? result : 0;
}
/***
* 验证开始日期是否合法,如果不合法,并返回修复后的正确日期毫秒数
* @param sdate
* @return
*/
private long validateStartTime(Calendar sdate)
{
if(sdate.get(Calendar.DAY_OF_WEEK) == 1)//开始日期从周日开始,如果开始时间为周末，自动修复为下周的9：00开始
{
sdate.add(Calendar.DATE,1);
sdate.setTimeInMillis(
sdate.getTime().getTime()- //从9点开始
(
((sdate.get(Calendar.HOUR_OF_DAY)-9) * 3600000)
+ (sdate.get(Calendar.MINUTE) * 60000)
+ (sdate.get(Calendar.SECOND) * 1000)
)
);
}else if(sdate.get(Calendar.DAY_OF_WEEK) == 7)//开始日期从周六开始
{
sdate.add(Calendar.DATE,2);
sdate.setTimeInMillis(
sdate.getTime().getTime()- //从9点开始,如果开始时间为周末，自动修复为下周的9：00开始
(
((sdate.get(Calendar.HOUR_OF_DAY)-9) * 3600000)
+ (sdate.get(Calendar.MINUTE) * 60000)
+ (sdate.get(Calendar.SECOND) * 1000)
)
);
}
return sdate.getTimeInMillis();
}

/***
* 验证结束日期是否合法,如果不合法,并返回修复后的正确日期毫秒数
* @param sdate
* @return
*/
private long validateEndTime(Calendar edate)
{
if(edate.get(Calendar.DAY_OF_WEEK) == 1)//结束日期是周日,如果结束日期是周六、周末自动修复为这周五18:00
{
edate.add(Calendar.DATE,-2);
edate.setTimeInMillis(
edate.getTime().getTime()+
(
18*3600000-(
(edate.get(Calendar.HOUR_OF_DAY) * 3600000)
+ (edate.get(Calendar.MINUTE) * 60000)
+ (edate.get(Calendar.SECOND) * 1000)
)
)
);
}else if(edate.get(Calendar.DAY_OF_WEEK) == 7)//结束日期是周六,如果结束日期是周六、周末自动修复为这周五18:00
{
edate.add(Calendar.DATE,-1);
edate.setTimeInMillis(
edate.getTime().getTime()+
(
18*3600000-(
(edate.get(Calendar.HOUR_OF_DAY) * 3600000)
+ (edate.get(Calendar.MINUTE) * 60000)
+ (edate.get(Calendar.SECOND) * 1000)
)
)
);
}
return edate.getTimeInMillis();
}
/***
* 计算两个日期间的工作日天数，除周六日
*
* @param sdate
* @param edate
* @return
*/
private long calcWorkdayTimeInMillis(Calendar sdate, Calendar edate,
long start, long end) {
// 获取开始时间的偏移量
long scharge = 0;
if (sdate.get(Calendar.DAY_OF_WEEK) != 1
&& sdate.get(Calendar.DAY_OF_WEEK) != 7) {
// 只有在开始时间为非周末的时候才计算偏移量
scharge += (sdate.get(Calendar.HOUR_OF_DAY) * 3600000);
scharge += (sdate.get(Calendar.MINUTE) * 60000);
scharge += (sdate.get(Calendar.SECOND) * 1000);
scharge = ((24 * 3600000) - scharge);
scharge += ((sdate.getTime().getTime() - start) - (3 * 24 * 3600000));
}
// (24*3600000=86400000)-((9*3600000+1800000)=34200000)+(3*24*3600000=259200000)-(2*24*3600000)=
// 86400000-34200000=52200000
// 获取结束时间的偏移量
long echarge = 0;
if (edate.get(Calendar.DAY_OF_WEEK) != 1
&& edate.get(Calendar.DAY_OF_WEEK) != (7)) {
// 只有在结束时间为非周末的时候才计算偏移量
echarge += (edate.get(Calendar.HOUR_OF_DAY) * 3600000);
echarge += (edate.get(Calendar.MINUTE) * 60000);
echarge += (edate.get(Calendar.SECOND) * 1000);
echarge = ((24 * 3600000) - echarge);
echarge += (edate.getTime().getTime() - end) - (24 * 3600000);
echarge -= (2 * 24 * 3600000);
}
// (24*3600000=86400000)-(18*3600000=64800000)+(24*3=259200000)
if (scharge < 0 || echarge < 0)
scharge = echarge = 0;
return scharge - echarge;
}
/**
* 获取两个时间之内的工作日时间（只去掉两个日期之间的周末时间，法定节假日未去掉）
*
* @param start
* -起始时间，共有3个重载方法，可以传入long型，Long型，与Date型
* @param end
* -结束时间，共有3个重载方法，可以传入long型，Long型，与Date型
* @return Long型时间差对象
*/
public Long getWorkdayTimeInMillisExcWeekend(long start, long end) {
return getWorkdayTimeInMillis(start, end);
}
/***
* 获取两个时间之内的工作日时间（去掉两个日期之间的周末时间，法定节假日时间）
*
* @param start
* @param end
* @return
*/
public Long getWorkdayTimeInMillisExcWeekendHolidays(String start,
String end, String format, List<Date> listHolidays) {
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date sdate;
Date edate;
try {
sdate = sdf.parse(start);
edate = sdf.parse(end);
return getWorkdayTimeInMillis(sdate.getTime(), edate.getTime(),
listHolidays);
} catch (ParseException e) {
e.printStackTrace();
return new Long(0);
}
}
public Long getWorkdayTimeInMillis(Long start, Long end) {
return getWorkdayTimeInMillis(start.longValue(), end.longValue(), null);
}
public Long getWorkdayTimeInMillis(Date start, Date end) {
return getWorkdayTimeInMillis(start.getTime(), end.getTime(), null);
}
public Long getWorkdayTimeInMillis(String start, String end, String format) {
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date sdate;
Date edate;
try {
sdate = sdf.parse(start);
edate = sdf.parse(end);
return getWorkdayTimeInMillis(sdate, edate);
} catch (ParseException e) {
e.printStackTrace();
return new Long(0);
}
}
private long getHolidaysInMillis(long start, long end,
List<Date> listHolidays) {
Calendar scalendar = Calendar.getInstance();
Calendar ecalendar = Calendar.getInstance();
int daysofH = 0;
try {
scalendar.setTimeInMillis(start);
ecalendar.setTimeInMillis(end);
if (listHolidays == null)
return new Long(0);
Iterator<Date> iterator = listHolidays.iterator();
while (iterator.hasNext()) {
Calendar ca = Calendar.getInstance();
Date hdate = iterator.next();
ca.setTime(hdate);
if (ca.after(scalendar) && ca.before(ecalendar)) {
daysofH = daysofH + 1;
} else if (ca.getTimeInMillis() == scalendar.getTimeInMillis()) {
daysofH = daysofH + 1;
} else if (ca.getTimeInMillis() == ecalendar.getTimeInMillis()) {
daysofH = daysofH + 1;
}
}
} catch (Exception e) {
e.printStackTrace();
return new Long(0);
}
return daysofH * 24 * 3600000;
}
private Calendar getNextMonday(Calendar cal) {
int addnum = 9 - cal.get(Calendar.DAY_OF_WEEK);
if (addnum == 8)
addnum = 1;// 周日的情况
cal.add(Calendar.DATE, addnum);
return cal;
}
/**
*
* @param 要转换的毫秒数
* @return 该毫秒数转换为 * days * hours * minutes * seconds 后的格式
*/
public String formatDuring(long mss) {
long days = mss / (1000 * 60 * 60 * 24);
long hours = (mss % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60);
long minutes = (mss % (1000 * 60 * 60)) / (1000 * 60);
long seconds = (mss % (1000 * 60)) / 1000;
return days + " days " + hours + " hours " + minutes + " minutes "
+ seconds + " seconds ";
}
/**
* 获取两个日期之间的实际天数，支持跨年
*/
public int getDaysBetween(Calendar start, Calendar end) {
if (start.after(end)) {
Calendar swap = start;
start = end;
end = swap;
}
int days = end.get(Calendar.DAY_OF_YEAR)
- start.get(Calendar.DAY_OF_YEAR);
int y2 = end.get(Calendar.YEAR);
if (start.get(Calendar.YEAR) != y2) {
start = (Calendar) start.clone();
do {
days += start.getActualMaximum(Calendar.DAY_OF_YEAR);
start.add(Calendar.YEAR, 1);
} while (start.get(Calendar.YEAR) != y2);
}
return days;
}
}

由于每年节假日不同,需要自己录入,有些周末工作日需要加班,所以说这个算法不准确,需要部分改动